((Subscript[K, i])=(∫_0^(π/2))  ((d θ)/(((1-(Subscript[m, i])(sin^2)θ))^(1/2)))[Equation   3](Subscript[E, i])=(∫_0^(π/2))(((1-(Subscript[m, i])(sin^2)θ))^(1/2)) d θ[Equation   4])